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51 8  Matrix methods of structural analysis

                 This displacement function may be taken as a polynomial which must include four
                 arbitrary  constants  corresponding  to  the  four  nodal  degrees  of  freedom of  the
                 element. Thus
                                        v(x) = a1 + Q2X + a32 + a4x3               (12.54)

                 Equation (12.54) is of the same form as that derived from elementary bending theory
                 for a beam  subjected to concentrated loads and moments and may  be  written in
                 matrix form as








                 or in abbreviated form as
                                             {V(X>)  = [f(x>1{4                    (12.55)

                 The rotation 8 at any section of the beam-element is given by av/ax; therefore
                                                        +
                                           e = a2 + 2a3~ 3a4x2                     (12.56)
                 From Eqs (12.54) and (12.56) we can write down expressions for the nodal displace-
                 ments vi, Bi and vj, 0,  at x = 0 and x = L respectively. Hence

                                        vi = a1
                                        ei = a2
                                                                                   (12.57)
                                        vj = a1 + a2L + a3L2 + a4L3
                                        e,  = a2 + 2a3L + 3a4L2
                 Writing Eqs (12.57) in matrix form gives

                                                10 0

                                                                                   (12.58)
                                                1  L  L2


                 or
                                               (0 = [-4l{a)                        (12.59)
                   The third step follows directly from Eqs (12.58) and (12.55) in that we express the
                 displacement at any point in the beam-element in terms of the nodal displacements.
                 Using Eq. (12.59) we obtain

                                              {a> = [-4-11{0                       (12.60)
                 Substituting in Eq. (12.55) gives
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