Page 135 - MarceAlgebra Demystified
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122                                                 CHAPTER 6 Factoring



                        each term as a product of the factor and something else (this step will
                        become unnecessary once you are experienced). Third apply the distribu-
                        tion property in reverse.


                             Examples

                             4 þ 6x

                             Each term is divisible by 2, so factor 2 from 4 and 6x:4 þ 6x ¼ 2   2 þ
                             2   3x ¼ 2ð2 þ 3xÞ:
                                    2
                             2x þ 5x ¼ x   2 þ x   5x ¼ xð2 þ 5xÞ
                               2
                             3x þ 6x ¼ 3x   x þ 3x   2 ¼ 3xðx þ 2Þ

                             8x þ 8 ¼ 8   x þ 8   1 ¼ 8ðx þ 1Þ

                                      2     2                          2                2
                             4xy þ 6x þ 2xy ¼ 2x   2y þ 2x   3x þ 2x   y ¼ 2xð2y þ 3x þ y Þ
                             Complicated expressions can be factored in several steps. Take for
                                                     4
                                          5 3 6
                                                               6 2
                                                        3
                             example 48x y z þ 60x yz þ 36x y z, each term is divisible by
                             12xyz. Start with this.
                                            4
                                 5 3 6
                                               3
                                                     6 2
                                                                                      3 2
                                                                      4 2 5
                              48x y z þ 60x yz þ 36x y z ¼ 12xyz   4x y z þ 12xyz   5x z
                                              5            4 2 5     3 2     5
                                  þ 12xyz   3x y ¼ 12xyzð4x y z þ 5x z þ 3x yÞ
                                                                        2
                             Each term in the parentheses is divisible by x :
                                                                          2
                                                                                    3
                                                                               2
                                                       2
                                                            2 2 5
                                                                    2
                                         3 2
                                4 2 5
                                                 5
                              4x y z þ 5x z þ 3x y ¼ x   4x y z þ x   5xz þ x   3x y
                                                       2   2 2 5      2    3
                                                    ¼ x ð4x y z þ 5xz þ 3x yÞ
                                 5 3 6      4  3     6 2            2   2 2 5      2     3
                              48x y z þ 60x yz þ 36x y z ¼ 12xyz   x ð4x y z þ 5xz þ 3x yÞ
                                                                3     2 2 5     2     3
                                                          ¼ 12x yzð4x y z þ 5xz þ 3x yÞ
                             Practice
                             1: 4x   10y ¼
                             2: 3x þ 6y   12 ¼
                                   2
                             3: 5x þ 15 ¼
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