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RISK ANALYSIS  499



                                        Table 12.5 Random Generation of Ten Values for the Parts Cost per Unit
                                        Trial                  Random Number               Parts Cost (E)
                                         1                         0.3125                      86.25
                                         2                         0.0053                      80.11
                                         3                         0.9209                      98.42
                                         4                         0.9768                      99.54
                                         5                         0.3584                      87.17
                                         6                         0.0390                      80.78
                                         7                         0.2161                      84.32
                                         8                         0.6333                      92.67
                                         9                         0.4391                      88.78
                                        10                         0.6991                      93.98




                                         Equation (12.3) generates a value for the parts cost. Let us use the bottom row of
                                      random numbers of Table 12.2 to simulate parts cost (once again it doesn’t matter
                                      which part of the table we use). With the first random number of 0.3125 we then
                                      have:

                                                            Parts cost ¼ 80 þ 0:3125ð20Þ¼ 86:25
                                      On the second trial we have a random number of 0.0082 simulating a parts cost of
                                      E80.11 and so on. Table 12.5 shows the generation of 10 values for the parts cost.
                      Spreadsheet packages  With appropriate choices of a and b, Equation (12.2) can be used to generate
                      such as Excel have built-  values for any uniform probability distribution.
                      in functions that make
                      simulations based on  Finally, we need a random number procedure for generating the first-year
                      probability distributions  demand. Because first-year demand is normally distributed with a mean of
                      such as the normal  15 000 units and a standard deviation of 4500 units (see Figure 12.2), we need
                      probability distribution  a procedure for generating random values from a normal probability distribu-
                      relatively easy.
                                      tion. Computer simulation packages and spreadsheets include a built-in function
                                      that provides randomly generated values from a normal probability distribution.
                                      In most cases the user only needs to provide the mean and standard deviation of
                                      the normal distribution. For example, using Excel the following formula can be
                                      placed into a cell to obtain a value for a probabilistic input that is normally
                                      distributed:
                                                        ¼ NORMINV(RAND(), Mean, Standard Deviation)


                                         Because the mean for the first-year demand in the PortaCom problem is 15 000
                                      and the standard deviation is 4500, the Excel statement:



                                                             ¼ NORMINV(RAND(),15 000,4500)             (12:4)


                                      will provide a normally distributed value for first-year demand. For example, if
                                      Excel’s RAND() function generates the random number 0.7005, the Excel function
                                      shown in equation (12.4) will provide a first-year demand of 17 366 units. If RAND()
                                      generates the random number 0.3204, equation (12.4) will provide a first-year
                                      demand of 12 900. Table 12.6 shows the results for the first ten randomly generated






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