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214      5 Non-Parametric Tests of Hypotheses


           Example 5.22
           Q: Consider the  Freshme n   dataset and  use the Kruskal-Wallis test in order to
           assess whether the freshmen performance (EXAMAVG) differs according to their
           attitude towards skipping the Initiation (Question 8).
           A: The mean ranks and results of the test are shown in Table 5.26. Based on the
           observed asymptotic significance, we reject the null hypothesis at a 5% level, i.e.,
           we have evidence that the freshmen answer Question 8 of the enquiry differently,
           depending on their average performance on the examinations.


           Table 5.26. Results, obtained with SPSS, for the Kruskal-Wallis test of average
           freshmen performance in 5 categories  of answers to  Question  8: a) ranks; b)
           significance.

             Q8                  N         Mean Rank               EXAMAVG
             1                   10          104.45
             2                   22          75.16       Chi-Square   14.081
             3                   48          60.08
             4                   39          59.04       df             4
             5                   12          63.46       Asymp. Sig.  0.007
             Total              131
           a                                            b


           Example 5.23
           Q: The variable ART of the Cork Stoppers’ dataset was analysed in section
           4.5.2.1  using  the one-way  ANOVA test. Perform the same analysis using the
           Kruskal-Wallis test and estimate its power  for the alternative  hypothesis
           corresponding to the sample means.
           A:  We saw in 4.5.2.1 that a logarithmic  transformation  of  ART was  needed in
           order to be able to apply the ANOVA test. This transformation is not needed with
           the Kruskal-Wallist test, whose  only assumption is  the independency of the
           samples.
              Table 5.27 shows the results, from which we conclude that the null hypothesis
           of median equality of the three populations is rejected at a 5% significance level
           (or even at a smaller level).
              In order to estimate the power of this Kruskal-Wallis test, we notice that the
           sample size is large, and therefore, we expect the power to be the same as for the
           one-way ANOVA test using a number of cases equal to n = 50×0.955 ≈ 48. The
           power of the one-way ANOVA, for the alternative hypothesis corresponding to the
           sample means and with n = 48, is 1.
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