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Parallel Resonance



                                              +
                                      I S                         C   I
                                              V G    I G  L  `  I L    C


                           Figure 2.8. Parallel GLC circuit for defining parallel resonance

         The admittance   of this circuit is given by
                        Y
                                                                       1
                                                                                         1 ·
                                                                                  §
                                                        S
                  Admittan ce =  Y =  Phasor Current   I ---- =  G + jZC +  --------- =  G +  j ZC –  -------
                                     ------------------------------------- =
                                     Phasor Voltage    V              jZL         ©     ZL  ¹
         or
                                     2              2     – 1
                             Y =   G +     ZC1 ZL ‘    tan     ZC –  1 ZL e  G                 (2.12)
                                             –


                                                e
                                                                    e
         Therefore, the magnitude and phase angle of the admittance   are:
                                                                  Y
                                               2
                                      Y =    G +      ZC 1   e  ZL       2                     (2.13)
                                                       –
         and
                                                  – 1    ZC – 1 ZL
                                                           e
                                         T =  tan  ---------------------------------           (2.14)
                                          Y
                                                         G
         The frequency at which the inductive susceptance B =    1 ZL   and the capacitive susceptance
                                                                  e
                                                             L
         B C  =  ZC   are equal is, again, called the resonant frequency and it is also denoted as Z 0   We can find
                              C
                        L
         Z   in terms of   and   as before.
           0
         Since
                                                          1
                                                  Z C –  ---------
                                                    0
                                                        Z L
         then,                                            0
                                                          1
                                                  Z C =  ---------
                                                   0
                                                         Z L
         and                                              0

                                                      1
                                               Z =   -----------                               (2.15)
                                                 0
                                                      LC
         as before. The components of  Y   are shown on the plot of Figure 2.2.






        Circuit Analysis II with MATLAB Applications                                              2-7
        Orchard Publications
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