Page 141 - Electrical Installation in Hazardous Area
P. 141

Calculation of release rates and extents  107

                  4.2 Release of  liquid below its atmospheric boiling point

                  The release of  a liquid below its atmospheric boiling point from an orifice
                  will take the form of  a jet  or, where the upstream pressure is sufficiently
                  high, a mist. The classic formula for release of  a liquid from an orifice or
                  nozzle is as follows:
                                         G = Ca[2al(P - 105]0.5                 kg/s4
                    where  G = Mass release                                     kg/s
                           a = Orifice area                                       m2
                           p = Upstream pressure                               N/m2
                           C = Discharge coefficient                               -
                           ~1  = Liquid density at
                               atmospheric conditions                          kg/m3

                    As before, C has a maximum value of  around 0.8 and therefore the equa-
                  tion becomes:
                                        G - 1.13 a [al(P - 105]0.5  kg/s (Equation 4.13)

                    If  no mist is formed then no significant hazardous area will surround the
                  leak (unless liquid is further contained around the point of  leakage) and
                  a liquid jet will exit the orifice, forming a pool of  liquid where it reaches
                  the floor or ground. The time taken for this jet to reach the ground can be
                  calculated using Newton’s Laws of  Motion:
                    Using v = u + at, where v is the final velocity, u is the initial velocity,
                  and a is the acceleration due to gravity, the following is the case for a jet
                  released at an angle above horizontal:
                                            v  sin@-@, =o
                    where  Q,  = Angle of  release above horizontal
                           g = Gravity acceleration (9.81 m/s2)
                           tl  = Time to apex of  jet (final velocity = 0 at apex)

                  Alternatively:
                                             t] = vsin@/g                        Secs
                  Using the relationship v2 = u2 + 2gS, where S is the vertical distance above
                  the release point which the apex reaches,
                                        (v sin   - 2  x g x s = o
                                        s = (vsin al2/2g                           m
                    If  the  initial release  is  at height h  then  the total height becomes  [h+
                  (v sin Q,)*/2 g] and the time for the jet to reach the ground or floor can be
                  calculated using the relationship;

                                             S = ut + 0.5gP
                    where u = 0
   136   137   138   139   140   141   142   143   144   145   146