Page 97 - Finite Element Modeling and Simulations with ANSYS Workbench
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82                    Finite Element Modeling and Simulation with ANSYS Workbench



                                          3000 lb               3000 lb

                                           72,000 lb-in.  72,000 lb-in.
                                  3000 lb  1        1         2


                                           2                 3

                                          3                   4




                  In local coordinate system, the stiffness matrix for a general 2-D beam element is

                                                 i θ                   j θ
                                  u i    v i            u j    v j
                                  EA                   EA               
                                  L      0      0    −  L     0      0  
                                                                        
                                  0    12 EI   6 EI    0    −  12 EI  6 EI  
                                         L 3    L 2           L 3    L 2  
                                        6 EI   4 EI I         6 EI   2 EI  
                                  0      2             0    −  2        
                             k  =       L      L             L      L  
                                 −   EA  0      0     EA      0      0  
                                  L                    L                
                                        12 EI   6 EI         12 EI   6 EI 
                                  0    −  3   −  2     0       3    −  2 
                                         L      L             L       L  
                                  0     6 EI   2 2EI   0    −  6EI   4EI  
                                        L 2    L             L 2    L  

                  Element Connectivity Table


                             Element           Node i (1)          Node j (2)
                             1                    1                   2
                             2                     3                  1
                             3                     4                  2



                  For element 1, we have
                                                       1 θ                   2 θ
                                       u 1    v 1            u 2     v 2
                                      141 7 .  0     0    − 141 7 .  0     0 
                                                                              
                                              .
                                                                    0 784
                                                                             4
                                      0     0 784   56 4 .  0     − .     56.4  
                                      0      564 .  5417    0     − 564 .  2708 
                                  4
                       k 1 = k′ 1 =  10 ×                                     
                                     − 141 7 .  0    0     141 7 .  0      0  
                                      0     − 0 784  − 56 4 .  0   0 784  − 56.4 4 
                                                                    .
                                               .
                                                                              
                                       0    564 .  2708    0     − 564 .  5417  
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