Page 147 - Fundamentals of Water Treatment Unit Processes : Physical, Chemical, and Biological
P. 147

102                            Fundamentals of Water Treatment Unit Processes: Physical, Chemical, and Biological



            TABLE Ex6.2
            Dimensions of Ideal Basin with Illustration of Trade-Offs
                 Q                v o
                                                  wL          v H        wD           D          w          L
                                         2
              3
                                                                           2
                                                   2
            (m =s)  (mgd)   (m=s)   (gpm=ft )    (m )        (m=s)       (m )        (m)        (m)        (m)
            0.05           0.00204               24.55       0.30        0.17        0.30       0.56       44.18
                    1.14             3.00
            0.05           0.00204               24.55       0.30        0.17        0.10       1.67       14.73
                    1.14             3.00
            0.05           0.00204               24.55       0.10        0.50        0.30       1.67       14.73
                    1.14             3.00
            0.05           0.00204               24.55       0.05        1.00        0.30       3.33        7.36
                    1.14             3.00
            Given          Table 6.9 for clay  v o ¼ Q=wL   Assumed  wD ¼ Q=v H    Assume D  W ¼ (wD)=D  L ¼ (wL)=w
                                              (Equation 6.11)         (Equation 6.12)



                                                               L




                                                                v H
                                             v H
                             D
                                     v 1                v =v o
                                                         s
                                 d                                        Path of discrete particle


            FIGURE 6.8 Removal of particles having fall velocity, v 1 , where v 1 < v o .


            where
              r 1 is the fraction of particles having velocity v 1 that will be  BOX 6.3  CONVERSION OF DEPTH
                removed (fraction)                                       RATIO TO VELOCITY RATIO
              d 1 is the depth at entrance of the basin of intercept of vector
                                                                 To convert Equation 6.13 to a more useful form,
                for particles with fall velocity, v 1 , extrapolated from the
                                                                 i.e., Equation 6.17, consider two similar triangles in
                far right intercept with the basin floor (m)
                                                                 Figure 6.8, i.e.,
              DP 1 is the portion of particles having diameter, d 1 ,
                expressed as a decimal fraction
                                                                                    d 1  v 1
                                                                                                         (6:15)
                                                                                       ¼
              A visual rationale for Equation 6.13 is then evident                  L    v H
            in Figure 6.8. To extend this idea, replace d 1 =D in
                                                                 and
            Equation 6.13 by v 1 =v o , i.e., Equation 6.17 in Box 6.3,
            to give
                                                                                    v o  D
                                                                                                          (6:8)
                                                                                       ¼
                                                                                    v H  L
                                    v 1
                                      DP 1              (6:14)
                               r 1 ¼
                                    v o                          Now divide Equation 6.15 by Equation 6.8, i.e.,
            where v 1 is the fall velocity of particles having equivalent         d 1 =L ¼ v 1 =v H
                                                                                                         (6:16)
            diameter, d 1 (m=s).                                                  D=L ¼ v o =v H
              In other words, for a particular group of particles with
                                                                 to give
            fall velocity v 1 , the proportion of particles removed is
            given by Equation 6.14. This notion was carried further by
            Camp to provide a rationale for summing these partial                   d 1  ¼  v 1          (6:17)
            removals for all particles, v s < v o , of a suspension (see            D    v o
            Section 6.4).
   142   143   144   145   146   147   148   149   150   151   152