Page 133 - Handbook of Civil Engineering Calculations, Second Edition
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1.116           STRUCTURAL STEEL ENGINEERING AND DESIGN

                                                               Thus, for a rectangle, C   bdf y /2, a
                                                                              2
                                                             d/2, and M p   aC   bd f y /4. For a circle, C
                                                                d f y /8, a   4d(3 ), and M p   aC
                                                                 2
                                                              3
                                                             d f y /6. For a W16   40, C   /2(11.77 sq.in.)
                                                                                 1
                                                               5.885f y .
                                                               To locate the action lines, refer to the
                                                             Manual and note the position of the cen-
                                                             troidal axis of the WT8   20 section, i.e., a
                                                             section half the size of that being considered.
                                                             Thus,  a   2(8.00 – 1.82)    12.36 in.
                                                             (313.944 mm); M p   aC   12.36(5.885f y )
                           FIGURE 20. Conditions at section of
                           plastification.                   72.7f y .
                                                             3. Divide M p by M y to obtain
                                                             the shape factor
                                                                                    2
                                                                              2
                                                             For a rectangle, SF   (bd /4)/(bd /6)   1.50.
                                                                                  3
                                                                             3
                                                             For a circle, SF   (d /6)/( d /32)   1.70.
                                                             For a WT16   40, SF   72.7/64.4   1.13.
                            4. Explain the relative values of the shape factor
                            To explain the relative values of the shape factor, express the resisting moment con-
                            tributed by a given fiber at plastification and at initial yielding, and compare the results.
                            Let dA denote the area of the given fiber and y its distance from the neutral axis. At plas-
                                                                         2
                            tification, dM p   f y ydA. At initial yielding, f   f y y/c; dM y   f y y dA/c; dM p /dM y   c/y.
                              By comparing a circle and a hypothetical W section having the same area and depth,
                            the circle is found to have a larger shape factor because of its relatively low values of y.
                              As this analysis demonstrates, the process of plastification mitigates the detriment that
                            accrues from placing any area near the neutral axis, since the stress at plastification is in-
                            dependent of the position of the fiber. Consequently, a section that is relatively inefficient
                            with respect to flexure has a relatively high shape factor. The AISC Specification for elas-
                            tic design implicitly recognizes the value of the shape factor by assigning an allowable
                            bending stress of 0.75f y to rectangular bearing plates and 0.90f y to pins.
                            DETERMINATION OF ULTIMATE LOAD
                            BY THE STATIC METHOD

                            The W18   45 beam in Fig. 21a is simply supported at A and fixed at C. Disregarding the
                            beam weight, calculate the ultimate load that may be applied at B (a) by analyzing the be-
                            havior of the beam during its two phases; (b) by analyzing the bending moments that exist
                            at impending collapse. (The first part of the solution illustrates the postelastic behavior of
                            the member.)


                            Calculation Procedure:
                            1. Calculate the ultimate-moment capacity of the member
                            Part a: As the load is gradually increased from zero to its ultimate value, the beam passes
                            through two phases. During phase 1, the elastic phase, the member is restrained against ro-
                            tation at C. This phase terminates when a plastic hinge forms at that end. During phase 2-the
                            postelastic, or  plastic, phase—the member functions as a simply supported beam. This
                            phase terminates when a plastic hinge forms at B, since the member then becomes unstable.
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