Page 451 - Industrial Power Engineering and Applications Handbook
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Testing of metal-enclosed switchgear assemblies 14/425

         Coils of the timers                            and totalled. This is the loss at the ambient temperature
         Control fuses                                  at the test place. It may be corrected to the operating
         Coils of the measuring instruments (A, kWh and kW   temperature of the assembly as shown in Table 14.5.
         meters etc.)                                   For sample calculations, we have considered it to be
         Wattage of the indicating lights               90°C. Table  14.4 provides  a step-by-step procedure
         VA burden of the instrument and control transformers   for estimation. The total watt loss of the assembly so
         and Control terminals etc.                     determined  is  an  estimate  for  the  required  heaters
         The VA burden and the corresponding p.f. of all such   that may be installed inside the assembly, to achieve
         components are provided by their manufacturers. VA   almost a true replica of the watt loss, as during actual
         cos$ is the content of watt loss. For more details see   operation.  These  heaters  are  located  within  the
         Section 15.6.l(iii).                           assembly under test to circulate heat uniformly to all
      3  Power connections and control wiring  The loss   parts to reach a rapid thermal equilibrium. To provide
         within such components is measured by their resistance,   heaters  for  individual  feeders  is  very  cumbersome
         which, in the case of cables, is a function of their size   and serves no purpose. The operating conditions are
         and length. The loss in the external power cables is   simulated similarly in the adjacent panel sections and
         calculated  similarly,  parts  of  which  run  inside  the   heaters are provided  there also. If  the bus rating  of
         assembly to connect the various feeders, by measuring   these sections is different from the rating of the section
         their average length inside the assembly.      under  test,  then  the heating  effect  of  these  busbars
          Calculating the resistance of each current-carrying   should also be estimated and the rating of the heaters
         component  separately is  a  very  cumbersome  and   altered to account for this.
         lengthy  procedure,  in  addition  to  being  not  very
         accurate due to the large number of  approximations.   Main busbars (horizontal and vertical)
         Some of  the joints  and  components  may  still  have
         been omitted from these calculations. The easier and   During  the  test  the  main  busbars  are  fed  at  the  rated
         more  often  recommended  procedure  is  to  measure   current, for which the switchgear assembly is designed.
         the resistance between the extreme ends of each feeder   They are heated naturally and therefore no resistance of
         in its ON condition by an Ohm-meter. This resistance   the main bus need be measured. The busbars are shorted
         will also include the contact resistance of each terminal   at one end and the current is fed from the other through
         and joint.                                  a variable-current  injection set at a reduced  voltage  of
          With the rating of each feeder and the resistance so   3-10  V,  or  enough  to  achieve  the  rated  current.  The
         obtained, the 12R loss of each feeder can be calculated   arrangement saves on power requirement  and consum-


      -                     -                             ~
      Table 14.4  Computation of heat losses for temperature rise test (single-line diagram,  Figure 14.1)
      S,:   Component       No. of   Feeder   Component   Watt loss (PR) at room   Watt loss at operating
      no.                   feeders   rating, (I)  resistance per pole  temperature   temperature of  90°C
                                   A        R mUpole      (32 "C) W, watts    W, watts
      (A)   Power circuits
      1    55 kW DOL feeder,   1   110      Circuit resistance   1 x 3 x 1 io2 x 0.33 x   Since W - R and
           Comprising;                      between I/C and   = 11.98         Rgo = R32  [I + -20  (90 - 32)]
           1 No. Switch - 250A              OIG power                         :.  W, at 9OoC,
           3 Nos. Fuses - 200A              terminals covering                = W, . [I + "20(90  - 32)]
           1 No. Relay - 90-50A             all components and                = 11.98 [l + 3.93 x 10-3(58)]
                                            power wiring or                   = 14.71
                                            metallic links and                (xz0 for copper from
                                            their contact                     Table 30.1
                                            resistances,                      = 3.93 x   per "c)
                                            including end
                                            terminations. By
                                            measurement
                                            = 0.33
      2    5.5 kW DOL feeders,   2   12     As above = 0.52   2 x 3 x 122 x 0.52 x 10-~  0.45 [l + 3.93 x   (58)]
           each comprising                                = 0.45              = 0.55
           1 No. Switch - 63A
           3 Nos. Fuses - 25A
           1  No. Contactor - 16A
           1 No. Relay - 9 - 14A
      3    SFU feeder comprising  1   32    As above = 0.46   1 x 3 x 32'x  0.46 x   1.41[1 + 3.93 x   (58)]
           1 No. Switch - 63A                             = 1.41              = 1.73
           3 Nos. Fuses - 32A
           Total loss in power                            = 16.99 W
           circuits
                                                                                            (Contd)
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