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6: REMOTE SENSING  109


                 transmitted to earth for storage on Computer  ness, of that very small area within the scene.
                 Compatible Tapes (CCTs). These tapes are then  Satellite scanners look through the atmosphere
                 processed on a computer to produce images.   at the earth’s surface, and the sensor therefore
                 The width of scene dimensions on the surface  measures the reflected radiation from the sur-
                 under the satellite (its swath) is 185 km. The  face and radiation scattered by the atmosphere.
                 data are (for convenience) divided into sets that  The pixel value represents both. Fortunately,
                 equal 185 km along its path.                 the level of scattered radiation is nearly con-
                   The satellites have a polar, sun synchronous  stant, so changes in pixel value are essenti-
                 orbit, and the scanners only record on the   ally caused by changes in the radiance of the
                 southbound path (Fig. 6.2) because it is night-  surface.
                 time on the northbound path. The paths of      The Instantaneous Field of View (IFOV) is
                 Landsats 1 to 3 shifted west by 160 km at the  the distance between consecutive measure-
                 equator each day so that every 18 days the   ments of pixel radiance (79 m × 79 m in MSS),
                 paths repeat resulting in repetitive, worldwide,  which is commonly the same as the pixel size
                 MSS coverage. Landsats 4, 5 and 7 and the Terra  (Table 6.1). However, MSS scan lines overlap,
                 satellite have a slightly different orbit result-  hence the pixel interval is less than the IFOV
                 ing in a revisit frequency of 16 days. Images  (56 m × 79 m). The TM and ASTER detectors
                 are collected at the same local time on each  have a greatly improved spatial resolution,
                 pass – generally between 9.30 and 10.30 a.m.  giving an IFOV of 30 m × 30 m.
                 to ensure similar illumination conditions on   The radiance for each pixel is quantified into
                 adjacent tracks. Successive paths overlap by  discrete gray levels and a finite number of bits
                 34% at 40°N and 14% at the equator. Landsat  are used to represent these data (Table 6.2).
                 does not give stereoscopic coverage, although  Table 6.2 shows how decimal numbers in the
                 it can be added digitally. ASTER does give   range 0–255 can be coded using eight indi-
                 stereoscopic coverage.                       vidual bits (0 or 1) of data. Each is grouped as an
                                                              8 bit “byte” of information, with each bit used
                                                                                                0
                                                              to indicate ascending powers of 2 from 2  (=1) to
                 6.2.2 Pixel parameters                        7
                                                              2  (=128). This scheme enables us to code just
                 Digital images consist of discrete picture ele-  256 (0–255) values. On the display terminal,
                 ments, or pixels. Associated with each pixel is  256 different brightness levels are used, cor-
                 a number that is the average radiance, or bright-  responding to different shades of gray ranging


                 TABLE 6.2 The principle of binary coding using 8 bit binary digits (bits).
                                Place values

                 Binary         2 7   2 6  2 5  2 4   2 3  2 2  2 1  2 0
                 Decimal        128   64   32   16    8    4    2    1

                                0     0    0    0     0    0    0    0   =    0
                                0     0    0    0     0    0    0    1   =    1
                                0     0    0    0     0    0    1    0   =    2
                                0     0    0    0     0    1    0    0   =    4
                                0     0    0    0     1    0    0    0   =    8
                                0     0    0    1     0    0    0    0   =    16
                                0     0    1    0     0    0    0    0   =    32
                                0     1    0    0     0    0    0    0   =    64
                                1     0    0    0     0    0    0    0   =    128
                                1     0    0    0     0    1    0    1   =    128 + 4 + 1
                                                                         =    133
                                1     1    1    1     1    1    1    1   =    128 + 64 + 32 + 16 + 8 + 4 + 2 + 1
                                                                         =    255
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