Page 433 - Marks Calculation for Machine Design
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P2: Sanjay
        P1: Shibu/Rakesh
                          January 4, 2005
                                      15:34
        Brown.cls
                 Brown˙C10
                                             MACHINE MOTION
                      As the angle (φ) of the crank and the lengths (L AB ) and (L BC ) are known, the angle (β)
                    can be determined from Fig. 10.7 using the law of sines as    415
                                                     ◦
                                         sin β  sin(90 − φ)
                                              =
                                          L AB     L BC
                                                                               (10.12)

                                                 L AB      ◦
                                         sin β =      sin(90 − φ)
                                                 L BC
                      Usingthegiveninformationandtheangle(β)foundfromEq.(10.12),theangularvelocity
                    of the connecting rod (ω rod ) can now be calculated from Eq. (10.10) and the velocity of the
                    slider (v slider ) can be calculated from Eq. (10.11).
                      As the angle (β) must be found using an equation based on applying the law of sines to
                    a scalene triangle that continually changes shape, there is no closed-form solution for the
                    angular velocity of the connecting rod and the velocity of the slider. Therefore, the analysis
                    must be done for multiple positions of the angle (φ).
                              U.S. Customary                      SI/Metric
                    Example 1. Determine the angular velocity  Example 1. Determine the angular velocity
                    (ω rod ) and velocity (v slider ) for a slider-crank  (ω rod ) and velocity (v slider ) for a slider-crank
                    linkage, where                     linkage, where
                     ω crank = 2,000 rpm                ω crank = 2,000 rpm
                        φ = 50 ◦                           φ = 50 ◦
                       L AB = 3in                        L AB = 7.5 cm
                       L BC = 8in                        L BC = 20 cm
                    solution                           solution
                    Step 1. Convert the angular velocity (ω crank )  Step 1. Convert the angular velocity (ω crank )
                    from (rpm) to (rad/s) as           from (rpm) to (rad/s) as
                                rev  2π rad  1 min                 rev  2π rad  1 min
                      ω crank = 2,000  ×  ×              ω crank = 2,000  ×  ×
                                min   1rev  60 s                   min  1rev   60 s
                          = 209 rad/s                        = 209 rad/s
                    Step 2. Substitute the given angle (φ), and  Step 2. Substitute the given angle (φ), and
                    the lengths (L AB ) and (L BC ), in Eq. (10.11) to  the lengths (L AB ) and (L BC ), in Eq. (10.11) to
                    determine the angle (β) as         determine the angle (β) as


                               L AB     ◦                        L AB     ◦
                        sin β =     sin (90 − φ)          sin β =    sin (90 − φ)
                               L BC                              L BC

                               3in                               7.5cm
                                                                           ◦
                                                                                ◦
                                        ◦
                                            ◦
                            =       sin (90 − 50 )            =        sin (90 − 50 )
                               8in                               20 cm
                            = (0.375) sin 40 ◦                = (0.375) sin 40 ◦
                            = 0.241                           = 0.241
                           β = sin −1 (0.241) = 14 ◦        β = sin −1 (0.241) = 14 ◦
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