Page 54 - Marks Calculation for Machine Design
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P1: Sanjay
                          January 4, 2005
                                      16:18
        Brown.cls
                 Brown˙C02
                  36
                                           STRENGTH OF MACHINES
                  2.2.1 Concentrated Force at Midpoint
                  The simply-supported beam in Fig. 2.9 has a concentrated force (F) acting vertically down-
                  ward at its midpoint. The distance between the supports is labeled (L), so the force (F) is
                  located half the distance (L/2) from each end support.
                                       L/2         F
                            A                                           B
                                                  L
                            FIGURE 2.9  Concentrated force at midpoint.
                  Reactions.  The reactions at the end supports are shown in Fig. 2.10—the balanced free-
                  body-diagram. Notice that the force (F) is split evenly between the vertical reactions (A y
                  and B y ), and because the force (F) is acting straight down, the horizontal reaction (A x ) is
                  zero. If the force (F) had a horizontal component, either left or right, then the horizontal
                  reaction (A x ) would be equal, but opposite in direction, to this horizontal component.

                                                  F
                        A  = 0
                         x


                             A  = F/2                                  B  = F/2
                                                                        y
                              y
                        FIGURE 2.10  Free-body-diagram.
                            U.S. Customary                       SI/Metric
                  Example 1. Determine the reactions at the  Example 1. Determine the reactions at the
                  ends of a simply-supported beam of length (L)  ends of a simply-supported beam of length (L)
                  with a concentrated force (F) acting at its mid-  with a concentrated force (F) acting at its mid-
                  point, where                       point, where
                    F = 12 kip = 12,000 lb             F = 55 kN = 55,000 N
                    L = 6ft                            L = 2m
                  solution                           solution
                  Step 1. From Fig. 2.10, calculate the pin reac-  Step 1. From Fig. 2.10 calculate the pin reac-
                  tions (A x and A y ) at the left end of the beam.  tions (A x and A y ) at the left end of the beam.
                    As the force (F) is vertical,      As the force (F) is vertical,
                               A x = 0                            A x = 0
                  and as the force (F) is at the midpoint,  and as the force (F) is at the midpoint,
                           F   12,000 lb                     F   55,000 N
                       A y =  =      = 6,000 lb          A y =  =       = 27,500 N
                           2     2                           2     2
                  Step 2. From Fig. 2.10, calculate the roller  Step 2. From Fig. 2.10, calculate the roller
                  reaction (B y ) at the right end of the beam.  reaction (B y ) at the right end of the beam.
                    As the force (F) is at the midpoint,  As the force (F) is at the midpoint,
                           F   12,000 lb                     F   55,000 N
                       B y =  =      = 6,000 lb          B y =  =      = 27,500 N
                           2     2                           2     2
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