Page 86 - Schaum's Outline of Theory and Problems of Electric Circuits
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AMPLIFIERS AND OPERATIONAL AMPLIFIER CIRCUITS
               CHAP. 5]
               5.9  DIFFERENTIAL AND DIFFERENCE AMPLIFIERS                                            75

                   A signal source v f with no connection to ground is called a floating source.  Such a signal may be
               amplified by the circuit of Fig. 5-19.



















                                                        Fig. 5-19
               Here the two input terminals A and B of the op amp are at the same voltage.  Therefore, by writing
               KVL around the input loop we get
                                              v f ¼ 2R 1 i  or  i ¼ v f =2R 1
               The op amp inputs do not draw any current and so current i also flows through the R 2 resistors.
               Applying KVL around the op amp, we have
                               v o þ R 2 i þ R 2 i ¼ 0  v o ¼ 2R 2 i ¼ 2R 2 v f =2R 1 ¼ ðR 2 =R 1 Þv f  ð15Þ

               In the special case when two voltage sources v 1 and v 2 with a common ground are connected to the
               inverting and noninverting inputs of the circuit, respectively (see Fig. 5-20), we have v f ¼ v 1   v 2 and
                                                  v o ¼ðR 2 =R 1 Þðv 2   v 1 Þ                      ð16Þ


               EXAMPLE 5.14   Find v o as a function of v 1 and v 2 in the circuit of Fig. 5-20.
                   Applying KCL at nodes A and B,


















                                                        Fig. 5-20


                                                     v A   v 2  v A
                       Node A:                             þ   ¼ 0
                                                       R 3   R 4
                                                   v B   v 1  v B   v o
                       Node B:                           þ       ¼ 0
                                                     R 1     R 2
               Set v A ¼ v B and eliminate them from the preceding KCL equations to get
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