Page 221 - Shigley's Mechanical Engineering Design
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                 196    Mechanical Engineering Design
                                 4–16     Using superposition for the bar shown, determine the minimum diameter of a steel shaft for
                                          which the maximum deflection is 2 mm.

                                           y
                                              250   250   250   250
                              Problem 4–16        375 N  550 N  375 N
                       Dimensions in millimeters.
                                                                     D
                                          O                              x
                                                 A     B     C

                                 4–17     A simply supported beam has a concentrated moment M A applied at the left support and a con-
                                          centrated force F applied at the free end of the overhang on the right. Using superposition, deter-
                                          mine the deflection equations in regions AB and BC.

                                             y
                                                      l          a   F
                              Problem 4–17
                                            A                  B     C   x
                                          M A
                                             R                 R
                                              1                 2
                                 4–18     Calculating beam deflections using superposition is quite convenient provided you have a com-
                                          prehensive table to refer to. Because of space limitations, this book provides a table that covers
                                          a great deal of applications, but not all possibilities. Take for example, Prob. 4–19, which fol-
                                          lows this problem. Problem 4–19 is not directly solvable from Table A–9, but with the addition
                                          of the results of this problem, it is. For the beam shown, using statics and double integration,
                                          show that
                                                  wa                wa 2         w            2           wa 2
                                              R 1 =  (2l − a)  R 2 =       V AB =  [2l(a − x) − a ]  V BC =−
                                                   2l                2l          2l                        2l
                                                  wx       2               wa 2
                                            M AB =   (2al − a − lx)  M BC =   (l − x)
                                                   2l                       2l
                                                   wx      2         3   2      2                 w       4
                                             y AB =    [2ax (2l − a) − lx − a (2l − a) ]  y BC = y AB +  (x − a)
                                                  24EIl                                         24EI
                                           y
                                                       l
                                                a
                              Problem 4–18      w
                                          A           B             C
                                                                       x
                                            R 1                     R 2

                                 4–19     Using the results of Prob. 4–18, use superposition to determine the deflection equations for the
                                          three regions of the beam shown.

                                           y
                                                       l
                                                   b
                                              a
                              Problem 4–19            w
                                                                    D
                                          A                            x
                                                  B         C
                                                                    R
                                            R 1                      2
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