Page 187 - Characterization and Properties of Petroleum Fractions - M.R. Riazi
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                                              4. CHARACTERIZATION OF RESERVOIR FLUIDS AND CRUDE OILS 167
                                  TABLE 4.9—Prediction of SCN groups from Eq. (4.27) for a gas condensate system
                                                          of Example 4.4.
                                           Actual data from Table 4.1  Predicted values from Eqs. (4.27)–(4.30) a
                                         mol% b                           mol% b
                              C N             Nor. b  M       SG              Nor. b   M      SG
                               7      0.80    26       95    0.7243   0.95     31      95    0.727
                               8      0.76    25      103    0.7476   0.69     22     107    0.749
                               9      0.47    15      116    0.7764   0.45     15     121    0.768
                              10+     1.03    34      167    0.8120   0.97     32     166    0.819
                              a Values of M and SG for SCN groups up to C 50 are taken from Table 4.6. C 10+ fraction represents SCN
                              groups from 10 to 50.
                              b Values of mol% in the first column represent composition in the whole original fluid while in the second
                              column under Nor. represent normalized composition for the C 7+ fraction.
            Eq. (4.10) is combined with Eq. (4.25), an equation for molar  use values of M n from Table 4.6 which yields B =−0.0276.
            distribution of hydrocarbon-plus fractions can be obtained as  Parameter A is calculated from Eq. (4.29) as: A =−4.2943.
                                                                  Using parameters A and B, normalized mole fractions for
            (4.26)          ln x n = A 1 + B 1 × M n              SCN from 7 to 50 are calculated from Eq. (4.27). Mole fraction
            which may also be written in the following exponential form.  of C 10+ can be estimated from sum of mole fractions of C 10
                                                                  to C 50 . M 10+ and SG 10+ are calculated as in Example 4.3 and
            (4.27)           x n = Aexp(B × M n )                 the summary of results are given in Table 4.9. In this method
                                                                  M 10+ and SG 10+ are calculated as 166 and 0.819, which are
            where B = B 1 and A = exp(A 1 ). It should be noted that A and
            B in Eq. (2.27) are different from A and B in Eq. (2.25). Para-  close to the actual values of 167 and 0.812.
            meters A 1 and B 1 can be obtained by regression of data be-
            tween ln(x n ) and M n such as those given in Table 4.2 for the  As shown in Example 4.4, the exponential model works well
            waxy oil. Most common case is that the detailed composi-  for prediction of SCN distribution of some gas condensate
                                                                  systems, but generally shows weak performance for crude oils
            tional analysis of the mixture is not available and only M 7+
            is known. For such cases coefficients A 1 and B 1 (or A and B)  and heavy reservoir fluids. As an example for the North Sea
            can be determined by applying Eqs. (4.23) and (4.24) assum-  oil described in Table 4.1, based on the procedure described
            ing that the mixture contains hydrocarbons to a certain group  in Example 4.4, M 10+ is calculated as 248 versus actual value
            (i.e., 45, 50, 60, 80, or even higher) without a plus fraction.  of 259. In this method we have used up to C 50 and the coef-
            This is demonstrated in Example 4.4.                  ficients of Eq. (4.27) are A = 0.2215, B =−0.0079. If we use
                                                                  SCN groups up to C 40 ,weget A = 0.1989 and B =−0.0073
            Example 4.4—Repeat Example 4.3 using the Pedersen expo-  with M 10+ = 246.5, but if we include SCN higher than C 50
            nential distribution model, Eq. (4.27).               slight improvement will be observed. The exponential distri-
                                                                  bution model as expressed in terms of Eq. (4.27) is in fact a
            Solution—For this case the only information needed are  discrete function, which gives mole fraction of SCN groups.
            M 7+ = 124 and x 7+ = 0.0306. We calculate normalized mole  The continuous form of the exponential model will be shown
            fractions from Eq. (4.27) after obtaining coefficients A and B.  later in this section.
            Since the mixture is a gas condensate we assume maximum
            SCN group in the mixture is C 50 . Molecular weights of C N  4.5.3 Gamma Distribution Model
            from 7 to 50 are given in Table 4.6. If Eq. (4.26) is applied to
            all SCN groups from 7 to 50, since it is assumed there is no  The gamma distribution model has been used to express
            N 50+ , for the whole C 7+ we have                    molar distribution of wider range of reservoir fluids including
                          50     50                               black oils. Characteristics, specifications, and application of

            (4.28)          x n =  Aexp(BM n ) = 1                this distribution model to molecular weight and boiling point
                          n=7    n=7                              have been discussed by Whitson in details [15, 17, 22, 23,
                                                                  36, 37]. The PDF in terms of molecular weight for this dis-
            where x n is normalized mole fraction of SCN group n in the
            C 7+ fraction. From this equation A is found as       tribution model as suggested by Whitson has the following
                                                                  form:
                                             −1

                                 50

                                                                                           α−1      M−η
            (4.29)          A =    exp(BM n )                                        (M − η)  exp −  β
                                 n=7                             (4.31)       F(M) =
                                                                                           β  (α)
                                                                                            α
            Parameter B can be obtained from M 7+ as
                                                                  where α, β, and η are three parameters that should be deter-
                          50             50
                        
             −1
                                                                  mined for each mixture and  (α) is the gamma function to
            (4.30)  M 7+ =  exp(BM n )     [exp(BM n )]M n        be defined later. Parameter η represents the lowest value of M
                          n=7            n=7
                                                                  in the mixture. Substitution of F(M) into Eq. (4.20) gives the
            where the only unknown parameter is B. For better accu-  average molecular weight of the mixture (i.e., M 7+ ) as:
            racy the last SCN can be assumed greater than 50 with M n
            calculated as discussed in Example 4.2. For this example we  (4.32)      M 7+ = η + αβ







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