Page 189 - Characterization and Properties of Petroleum Fractions - M.R. Riazi
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            AT029-Manual
                                              4. CHARACTERIZATION OF RESERVOIR FLUIDS AND CRUDE OILS 169
                                                                  following relation for the average molecular weight of the
                               Carbon Number, C
                                              N
                                                                  SCN group n:
                      0        20      40       60       80
                  0.01                                                            M 7+ − η        η
                                                                       M av,n =−         exp
                                                                                  x m,n      M 7+ − η
                                                                                    M +              M +
                 0.008                                                               n                n
                            1                                                ×    M 7+ − η  + 1 exp − M 7+ − η
                                                                                      M n −  + 1 exp −  M n −

                PDF, F  0.006  2                                                     M 7+ − η         M 7+ − η
                                                                 (4.48)
                                                                                 −
                                                                  where M av,n is the average molecular weight of SCN group n.
                 0.004                                            Equations (4.47) and (4.48) can also be applied to any group
                                2.5
                                                                  with known lower and upper molecular weight boundaries in
                                                                  aC 7+ fraction that follows an exponential distribution.
                 0.002                  3
                                                                  Example 4.5—Show that distribution model expressed by
                    0                                             Eq. (4.46) leads to Eq. (4.27) for exponential distribution of
                                                                  SCN groups.
                      0    200   400   600   800  1000  1200
                              Molecular Weight, M
                                                                  Solution—Equation (4.46) can be written in the following
                FIG. 4.9—Molar distribution by gamma density function  exponential form:
              (Eq. 4.31).
                                                                 (4.49)            F(M) = a exp(bM)
              In evaluation of the summation in Eq. (4.35), the gamma  where parameters a and b are given as
            function is defined as:
                                                                                      1          η
                                    ∞
                                                                               a =        exp
                                        e dt
            (4.43)            (x) =  t x−1 −t                                      M 7+ − η   M 7+ − η
                                                                 (4.50)
                                   0                                                   1
                                                                               b =−
            where t is the integration variable. As suggested by Whitson            M 7+ − η
            [15], the gamma function can be estimated by the following  Substituting Eq. (4.49) into Eq. (4.18) gives the following
            equation provided in reference [37]:
                                                                  relation for the cumulative mole fraction, x cm at molecular
                                                                  weight M:
                                         8
            (4.44)           (x + 1) = 1 +  A i x i
                                                                              M
                                        i=1
                                                                                              a

            where for 0 ≤ x ≤ 1, A 1 =−0.577191652, A 2 = 0.988205891,  (4.51)  x cm =  a exp(bM)dM =  b  [exp(bM) − exp(bη)]
            A 3 =−0.897056937, A 4 = 0.918206857, A 5 =−0.756704078,         η
            A 6 = 0.482199394,  A 7 =−0.193527818,  and   A 8 =
            0.035868343. And for x > 1, the recurrence formula may be  For a SCN group n with lower and upper molecular weights
                                                                      −
                                                                             +
                                                                            n
                                                                     n
            used:                                                 of M and M and use of Eq. (4.19) we get mole fraction of
                                                                  the group, x n :
            (4.45)             (x + 1) = x (x)
                                                                 (4.52)      x n =  a   exp(bM ) − exp(bM )
                                                                                                      −
                                                                                            +
                                                                                                      n
                                                                                            n
            where from Eq. (4.44),  (1) = 1 and thus from the above equa-         b
            tion  (2) = 1.                                        From Eqs. (4.39) and (4.40) we have
              Equation (4.31) with α = 1 reduces to an exponential dis-
            tribution form. From Eq. (4.33) with α = 1, β = M 7+ − η and        M n + M n+1       M n−1 + M n
                                                                             +
                                                                                              −
                                                                           M =              M =
                                                                            n
                                                                                              n
            substituting these coefficients into Eq. (4.31) the following            2                2
            density function can be obtained:
                                                                  Now if we assume the difference between M n and M n−1 is a
                                 1           M − η                constant number such as hwe have M n+1 = M n + hand M n−1 =

            (4.46)    F(M) =          exp −
                                                                                                −
                                                                               +
                              M 7+ − η      M 7+ − η              M n − h, thus M = M n + h/2 and M = M n − h/2. A typical
                                                                               n
                                                                                                n
                                                                  value for h is usually 14. Substituting for M n +  and M n −  in
            For a SCN group n, with molecular weight boundaries of M −
                                                             n    Eq. (4.52) gives
            and M , substitution of Eq. (4.46) into Eq. (4.19) will result:
                 +
                 n
                                                                            a


                               η                                       x n =   {exp[b(M n + h/2)] − exp[b(M n − h/2)]}
                 x m,n =−exp                                                b
                             M 7+ − η                                        
       bh         bh
                                                                            a
                                 M +             M −
                                                                 (4.53)  =      exp     − exp −     exp(bM n )
            (4.47)     × exp −     n    − exp −    n                        b        2          2
                               M 7+ − η         M 7+ − η
                                                                  This equation can be written as
            where x m,n is the mole fraction of SCN group n. Substitut-
            ing Eq. (4.46) in Eq. (4.21) for molecular weight gives the  (4.54)     x n = A exp(BM n )
                                          --`,```,`,``````,`,````,```,,-`-`,,`,,`,`,,`---
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