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Guo, Boyun / Computer Assited Petroleum Production Engg 0750682701_chap13 Final Proof page 202  3.1.2007 9:07pm Compositor Name: SJoearun




               13/202  ARTIFICIAL LIFT METHODS
                                                Shut-in pressure build-up curve
                           P WS




                           Bottom-hole pressure  A B  C D








                                     Valve  open  E  closed  Valve  open  Valve
                                             Valve
                                                             closed



                                   T 1              T 2               T 3
                                                   Time
                                  Figure 13.19 Illustrative plot of BHP of an intermittent flow.

                                                                                   P WS

                                                 Gradient of gas and
                                                 entrained liquid        Static Gradient
                                                 below slug



                           Pressure     Gradient of slug




                               Gradient in gas
                               Above slug
                         P SP



                                                      Slug                  Operating valve

                                                 Depth
                                  Figure 13.20 Intermittent flow gradient at midpoint of tubing.
               Example Problem 13.8 Determine the depth to the oper-  Solution The static gradient is
               ating (master) valve and the minimum GLR ratio for the
               following well data:                              G s ¼ 0:8762(0:433) ¼ 0:379 psi=ft:
                      Depth ¼ 8,000 ft                   Thus, the average flowing BHP is
                         p so ¼ 800 psig
                 3
                 2 ⁄ 8 -in. tubing ¼ 1:995 in: ID               P bhfave ¼ 2,000   1,000 ¼ 1,000 psig:
                 1
                 5 ⁄ 2 -in., 20 lb/ft casing             The depth to the static fluid level with the p tf ¼ 50 psig, is
                 No water production                                       2,000   50
                         g o ¼ 0:8762, 30 8API                 D s ¼ 8,000    0:379  ¼ 2,855 ft:
                    BHP (SI) ¼ 2,000 psig
                         PI ¼ 0:10 bbl=day=psi           The hydrostatic head after a 1,000 psi drawdown is
                         p tf ¼ 50 psig                                  1,000

                         t av ¼ 127 F                               D dds ¼  ¼ 2,639 ft:
                                                                         0:379
                 Cycle time: 45 minutes                  Thus, the depth to the working fluid level is
                 Desired production: 100 bbl/day
                         g g ¼ 0:80                          WFL ¼ D s þ D dds ¼ 2,855 þ 2,639 ¼ 5,494 ft:
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