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4.5 Inference on More than Two Populations   159


                 Sum of the squares representing the experimental error. The experimental
                 variance is v e = SSE/[rc(n – 1)], has rc(n – 1) degrees of freedom and is the
                                 2
                 point estimate of σ .
              6.  SSI = SSS – (SSC + SSR) = SST –  SSC – SSR – SSE.
                 The SSI term represents the influence on the experiment of the interaction
                 of the column and the  row effects. The variance  of  the  interaction,
                 v i = SSI/[(c – 1)(r – 1)] has (c – 1)(r – 1) degrees of freedom and is the point
                                  2
                            2
                 estimate of σ +  nσ .
                                  I

              Therefore, in the repeated measurements model, one can  no longer treat
           independently the column and row factors; usually, a term due to the interaction of
           the columns with the rows has to be taken into account.
              The ANOVA table for this experiment with additive and interaction effects is
           shown in Table 4.20. The “Subtotal” row corresponds to the explained variance
                                                                          ”
           due to both effects, Factor 1 and Factor 2, and their interaction. The  Residual  row
                                                                  “
           is the experimental error.

           Table 4.20. Canonical table for the two-way ANOVA test.
             Variance   Sum of Squares         df        Mean Square      F
             Source
             Columns    SSC                    c−1       v c = SSC/(c−1)   v c / v e
             Rows       SSR                    r−1       v r = SSR/(r−1)   v r / v e

             Interaction  SSI               (c−1)(r−1) v i = SSI/[(c−1)(r−1)]  v i / v e

             Subtotal   SSS=SSC + SSR + SSI   cr−1      v m = SSS/( cr−1)   v m/ v e
             Residual   SSE                  cr(n−1)   v e = SSE/[cr(n−1)]

             Total      SST                   crn−1


              The previous sums of squares can be shown to be computable as follows:
                    c  r  n
                                 2
                            2
              SST  = ∑∑∑ x  ijk  −T /( rcn) ,                             4.43a
                                ...
                    = i 1  = j 1  = k 1
                    c  r
                         2
                              2
              SSS =  ∑∑  x ij.  −T /( rcn)                                4.43b
                             ...
                    = i 1  = j 1
                    c
                                2
                        2
              SSC = ∑  ( T /  rn)  −T /( rcn) ,                           4.43c
                                ...
                        i..
                    = i 1
                     r
                        2
                                2
              SSR  =  ∑ T /( cn) −T /( rcn) ,                             4.43d
                       .
                        j.
                                ...
                     = j 1
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