Page 93 - Arrow Pushing in Inorganic Chemistry A Logical Approach to the Chemistry of the Main Group Elements
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3.3 GROUP 13-BASED REDUCING AGENTS  73
               3.3  GROUP 13-BASED REDUCING AGENTS

                                                               −
               Anionic hydrido complexes of the group 13 elements, MH , are widely used as reducing
                                                              4
               agents. Of these, lithium aluminum hydride (LiAlH , often abbreviated as LAH) and
                                                           4
               sodium borohydride (NaBH ) are probably the best known. LAH is a powerful reducing
                                      4
               agent (which reacts violently with water), which reduces essentially all reducible organic
               functional groups, including carbonyl compounds, esters, carboxylic acids, and nitriles.
                                                  1
                                                        2
               Shown below is the reduction of an ester, R COOR , by LAH:
                                      +
                           2
                      H   R O       Li      H          H        Li        H
                                                                     2
                    −                                            − LiR O
                     Al       C   O           Al  H +    C   O              C   O  (3.7)
                  H
                                                      2
                   H     H  R 1             H        R O  R 1             R 1
                                     −
                                   2
               The alkoxide anion (R O ) and AlH produced above now react together, forming
                                               3
                          −
                     2
               [Al(OR )H ] , which then continues to act as a hydride transfer agent:
                        3
                                     H                      H
                                 −     Al  H               −  Al
                                                       2
                                2
                               R O                    R O      H
                                                         H
                                     H
                                                              2
                               H     H                       R O
                                                     H     −
                              −                            O     Al  H
                               Al      C   O           C
                          2
                         R O                                                       (3.8)
                                  H
                            H        R 1             H  R 1    H      2
                                                                     R O
                                                                         −
                                                                H       Al  H
                                                                            H
                                                                  C   O
                                                               H
                                                                 R 1
               The anionic Al intermediate so produced still carries hydride ligands and therefore contin-
               ues its reducing action:
                                  2
                                R O      R O       Li  +      R O    Li  +
                                                               2
                                          2
                                     −                            −
                            H       Al  H    C   O               Al  OR 2
                                        H                            OCH 2 R 1     (3.9)
                                                           1
                              C   O        R 1            R H 2 CO
                           H
                             R 1
               Aqueous work-up then liberates the free alcohol:
                                  2
                                 R O
                                     −             O
                                        OR 2     H 2        1
                                    Al                    2 R CH OH + Al(OH) 3    (3.10)
                                                               2
                                                   2
                                        OCH 2 R 1  − 2 R OH
                              1
                             R H 2 CO
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