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26                    Finite Element Modeling and Simulation with ANSYS Workbench



            where B is the element strain–displacement matrix, which is

                                  d                  d                  ξ d
                                                                  ξ  ⋅
                              B =    N i  ξ ()  N j ()    N i  ξ ()  N j () 
                                                ξ  =
                                  dx                 d ξ               dx
            that is,

                                           B =−  1/L  1/L                            (2.14)
                                                         

              Stress can be written as

                                             σ= E ε= EBu                              (2.15)

              Consider the strain energy stored in the bar

                                        1           1
                                                           T
                                    U =   ∫ σ εdV  =  ∫ ( uB E Bu dV
                                            T
                                                         T
                                                                )
                                        2           2
                                          V          V
                                                      
                                             ∫
                                        1
                                                T
                                      =   u T   ( B E )   u                          (2.16)
                                                  B dV
                                        2             
                                            V         
            where Equations 2.13 and 2.15 have been used.
              The potential of the external forces is written as (this is by definition, and remember the
            negative sign)
                                                            T
                                         Ω= − fu        =−uf                          (2.17)
                                                     j
                                               ii  − fu j
              The total potential of the system is
                                               Π = U + Ω
              which yields by using Equations 2.16 and 2.17

                                                        
                                               ∫
                                          1
                                      Π=    u T   ( B E B)dV  u  − uf                (2.18)
                                                  T
                                                               T
                                          2             
                                              V         
              Setting dΠ = 0 by the principle of minimum potential energy, we obtain (verify this)
                                                     
                                            ∫ ( B E )  u =  f
                                                 B dV 
                                               T
                                                     
                                            V        
              or

                                                 ku = f                                (2.19)
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