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Bars and Trusses                                                             27



            where

                                            k = ∫  B (  T E B)dV                      (2.20)
                                                V
            is the element stiffness matrix.
              Equation 2.20 is a general result which can be used for the construction of other types
            of elements.
              Now, we evaluate Equation 2.20 for the bar element by using Equation 2.14
                                  L   −1/L                     1   −  1
                              k =  ∫ 1/L     −1/L  1/LAdx =  EA   −1  1  
                                                      
                                          E
                                   
                                                      
                                  0                         L        
            which is the same as we derived earlier using the direct method.
              Note that from Equations 2.16 and 2.20, the strain energy in the element can be written as
                                                   1
                                                     T
                                              U =   uku                               (2.21)
                                                   2
              In the future, once we obtain an expression like Equation 2.16, we can immediately rec-
            ognize that the matrix in between the displacement vectors is the stiffness matrix. Recall
            that for a spring, the strain energy can be written as
                                               1      1
                                           U =  k∆ 2  =  ∆ T k∆
                                               2      2
              Thus, result (2.21) goes back to the simple spring case again.


            2.4.3  Treatment of Distributed Load
            Distributed axial load  q (N/mm, N/m, lb/in) (Figure 2.6) can be converted into two
              equivalent nodal forces using the shape functions. Consider the work done by the distrib-
            uted load q,

                             L             L                        L
                                                                   ∫
                           1             1      T         1           Nx()
                                                                        i
                      W q =  ∫ u xqxdx =   ∫ (Nu )  q xdx =     u i  u j       qx dx
                                                                            ()
                               ()
                                                   ()
                                  ()
                           2             2                2           Nx() 
                                                                        j
                             0             0                        0
                               L
                           1
                         =  2  u T ∫  N T qx dx                                       (2.22)
                                   ()
                               0
                                                  q
                                          i     x           j
                                       f i q                 f j q
                                          i                 j

            FIGURE 2.6
            Conversion of a distributed load on one element.
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