Page 294 - Integrated Wireless Propagation Models
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272    C h a p t e r   F i v e


                                                        Receiver
















                                             Transmitter
               FIGURE 5.2.2.2.1  Top view-receiver in close-in region.


               where the thickness of the obstruction B is in feet. Equation (5.2.2.2.2) is from the empir­
               ical data. The close-in distance De is defined in Eq. (5.2.1.2.8).
                  This would give us a path loss L s shown in Eq. (5.2.2.2.1) and the power P, at the
                                             LO
               receiver shown in Eq. (5.2.2.1 . 4). The measurement shows that when the receiver is in
               the close-in region, the signal will be affected by penetrating through the wall. The sum
               of thickness of number of walls B is shown in Eq. (5.2.2.2.2) for calculating the excessive
               loss due to the obstruction.

               5.2.2.2.2   Receiver beyond the Close-in Region  When the receiver is located beyond the
               close-in region and obstructed by a wall or walls, a new component is added to the path
               loss. This loss is related to the wall thickness and the material that the wall is made of.
               In a building, walls that separate rooms are mostly made of the same material. The
               signal loss characteristics can be easily derived through a linear regression. This will be
               introduced in Sec.  5.3.4. Without measuring the actual wall thickness, which we do
               within the close-in distance, the measured data extrapolate an additional path-loss
               slope of the signal for penetrating through rooms, depending the material of the walls.
                  In Fig. 5.2.2.2.2, we see that d1 is the distance from the transmitter to the intersec­
               tion (wall) of the first room, while d2 is the distance from the intersection of the first
               room to the receiver. The radio path along d1 is in the direct LOS path from the trans­
               mitter. Hence, the path loss can have two components. The first one, L s due to d1 < d,
                                                                          LO
               is given as
                                    LOS -
                                              4
                                                 l
                                   L  - 20  og  - A-  F                         (5.2.2.2.1)
                                               7td +  LOS
                                           1
               The additional path-loss component (L,00,) due to the distance d2 from the first-room
               intersection to the receiver is given by
                                                (  � )
                                   L room = m,00, log  1 +   1                  (5.2.2.2.3)
               where m room  is the an additional path-loss slope of the signal for penetrating through
               rooms, depending the material of the walls; m room  is usually around 27 dB I dec.
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