Page 201 - Marks Calculation for Machine Design
P. 201

P1: Shibu
                                      14:25
                          January 4, 2005
                 Brown˙C04
        Brown.cls
                              U.S. Customary  COMBINED LOADINGS   SI/Metric       183
                    Step 2.  Calculate the maximum tangential  Step 2.  Calculate the maximum tangential
                    stress using Eq. (4.26).           stress using Eq. (4.26).
                                                                 2
                                2
                                r + R 2                           r + R 2
                       σ  max  = p  o                    σ  max  = p  o
                        t
                                2
                                                                 2
                               r − R 2                   t       r − R 2
                                o                                o
                                                                         2
                                     2
                           = (9,650 lb/in )                 = (48,680,000 N/m )
                                   2       2                          2       2
                                (4in) + (0.75 in)                (0.1m) + (0.02 m)
                             ×                                ×
                                                                      2
                                   2
                                (4in) − (0.75 in) 2              (0.1m) − (0.02 m) 2
                                     2
                                                                         2
                           = (9,650 lb/in )                 = (48,680,000 N/m )
                                (16 + 0.5625) in                 (0.01 + 0.0004) m
                                          2                                  2
                             ×                                ×
                                (16 − 0.5625) in 2               (0.01 − 0.0004) m 2
                                     2
                                                                         2
                           = (9,650 lb/in )                 = (48,680,000 N/m )
                                (16.5625) in                     (0.0104) m
                                        2                               2
                             ×          2                     ×         2
                                (15.4375) in                     (0.0096) m
                                                                         2
                                     2
                           = (9,650 lb/in )[1.073]          = (48,680,000 N/m )[1.083]
                                     2
                                                                         2
                           = 10,353 lb/in = 10.35 kpsi      = 52,737,000 N/m = 52.74 MPa
                    Step 3. From Eq. (4.27) the maximum radial  Step 3. From Eq. (4.27) the maximum radial
                    stress is                          stress is
                         σ r max  =−p =−9,650 lb/in 2     σ r max  =−p =−48,680,000 N/m 2
                             =−9.65 kpsi                      =−48.68 MPa
                    Step 4. Display the stresses found in steps 1,  Step 4. Display the stresses found in steps 1,
                    2, and 3, in kpsi, on the edge view of the stress  2, and 3, in MPa, on the edge view of the stress
                    element shown in Fig. 4.27.        element shown in Fig. 4.27.
                                   10.35                           52.74
                          9.65         9.65                48.68        48.68
                                   0.13                             1.15
                                   10.35                           52.74
                              Edge view                        Edge view
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