Page 206 - Marks Calculation for Machine Design
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P1: Shibu
                          January 4, 2005
                 Brown˙C04
        Brown.cls
                  188
                            U.S. Customary 14:25  STRENGTH OF MACHINES  SI/Metric
                  Step 4. Using the maximum bending moment  Step 4. Using the maximum bending moment
                  (M max ) found in step 3 calculate the maximum  (M max ) found in step 3 calculate the maximum
                  bending stress (σ max ) from Eq. (4.37).  bending stress (σ max ) from Eq. (4.37).
                            M max                             M max
                      σ max =                           σ max =
                              2
                                                                2
                            π r t                             π r t
                                                                m
                              m
                            (129,000 lb · ft)(12 in/ft)        (194,000 N · m)
                         =                                  =
                                                                   2
                                    2
                              π(36 in) (0.5in)                π(1m) (0.013 m)
                            1,548,000 lb · in                 194,000 N · m
                         =                                  =
                               2036 in 3                        0.0408 m 3
                                 2
                                                                       2
                         = 760 lb/in = 0.8 kpsi             = 4,750,000 N/m = 4.8MPa
                  Step 5. Combine the axial stress (σ axial ) found  Step 5. Combine the axial stress (σ axial ) found
                  in step 1 with the maximum bending stress  in step 1 with the maximum bending stress
                  (σ max ) found in step 4 to give a maximum nor-  (σ max ) found in step 4 to give a maximum nor-
                  mal stress (σ xx ).                mal stress (σ xx )
                        σ xx = σ axial + σ max            σ xx = σ axial + σ max
                           = (7.2 kpsi) + (0.8 kpsi)         = (53.8 kpsi) + (4.8 kpsi)
                           = 8.0 kpsi                        = 58.6 kpsi
                  Step 6. Display the stresses found in steps 2  Step 6. Display the stresses found in steps 2
                  and 5, in kpsi, on the stress element shown in  and 5, in MPa, on the stress element shown in
                  Fig. 4.31.                         Fig. 4.31.
                                  14.4                               107.6
                           0                                  0
                      8.0                 8.0            58.6               58.6
                                      0                                  0
                                  14.4                               107.6
                  Step 7. Display the stresses found in steps 2  Step 7. Display the stresses found in steps 2
                  and 5, in kpsi, on the stress element shown in  and 5, in MPa, on the stress element shown in
                  Fig. 4.32.                         Fig. 4.32.
                               0.2                                1.4
                                        8.0                               58.6
                   14.4                14.4          107.6                107.6

                         Outside of tank                    Outside of tank
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