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5. Static response of MEMS                                        289
         For the  amplification  scheme of Fig.  5.21  (b),  point 3  will  move due  to
         bending and axial deformations as follows:










         The horizontal  displacements    and      as well  as the  displacement
         amplification a are given by Eqs. (5.67), (5.68) and (5.69), respectively. The
         vertical displacement of point 1 in Fig. 5.21 (b) is:





         Example 5.12
             Assess the  errors  that  appear in the  amplification  produced by the
         microdevice of Fig.  5.21 (b)  when neglecting  the  axial  deformation  of the
          flexure  hinge.  Consider  that the  flexure has  a  constant  rectangular  cross-
         section and that         and

          Solution:
             When the axial deformation is accounted for, in addition to the bending-
         produced deformation,  the  horizontal  displacement at  point 3  can be
          calculated by means of Castigliano’s displacement theorem as:





          and the slope at the flexure’s tip is:





          For small  displacements, the  horizontal motions  at  points  1  and  2 can  be
          approximated as:








          and the corresponding displacement amplification becomes:
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