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176   5 Near Field
                                                     480 nm

                                                                     (a) d = 34 nm
                                                                     (b) d = 68 nm
                                                       280 nm        (c) d = 136 nm


                                                       d
                                                                    640 nm
                                                                     Clad
                                                                      Core
                                             320
                                             nm                       Clad





                                                   Plane wave
                            Fig. 5.9. 2-D Cartesian computational domain of 480 nm × 640 nm for calculation
                            of E x around tapered fiber end with silica core and perfect conductor clad. Here,
                            the refractive index and electrical permittivity of silica are 1.46 and 2.25ε r,(ε r:
                            free-space permittivity), respectively



                            Example 5.4. Compute the scattered light field from an optically trapped gold
                            particle in the evanescent light, which is produced by a total reflection on a
                            prism–air interface.

                            Solution. First, we produce an evanescent light by the incident s-polarized
                            plane wave expressed by the followingequations at an angle of θ =45 with
                                                                                         ◦
                            a wavelength of λ = 488 nm:
                                                     √

                                                       ε r
                             E z (i, j)=sin 2πf  n∆t −   (i − 1)∆x sin θ  ,
                                                      c
                                                              √
                                                      1         ε r                ∆y

                            H y (i, j)= − sin 2πf  n −   ∆t −       (i − 1)∆x sin θ +  cos θ
                                                      2        c                    2
                                        √
                                         ε r
                                      ×     cos θ,
                                         Z
                                                            √                     √

                                                    1         ε r                  ε r
                            H x (i, j)=sin 2πf  n −    ∆t −     (i − 1)∆x sin θ  ×   sin θ.
                                                    2        c                     Z
                            Here, f = c/λ, c is the speed of light in vacuum, ε r is the free-space permit-
                            tivity and Z is the intrinsic impedance.
                               Next, a 100-nm-diameter perfect conductor sphere is located 10 nm above
                            the surface of the prism and the electromagnetic field near the surface is
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