Page 257 - Renewable Energy Devices and System with Simulations in MATLAB and ANSYS
P. 257

244             Renewable Energy Devices and Systems with Simulations in MATLAB  and ANSYS ®
                                                                                ®


                         1.2                                      l e =l e0 , l s =0
                                                                        , l =ln
                                                                  l =l e0max s
                                                                   e
                         0.8
                         0.4
                       Flux density (T)  –0.4 0






                        –0.8


                        –1.2
                           0       1        2       3       4       5       6
                     (c)                       Electrical angle (rad)


            FIGURE 9.31 (Continued )  FEM key validation on optimal design of 7.6 MW, 11 rpm DCE-SG: (c) radial
            air-gap flux density (at no load and full load).




                                         2     j 2π   − j 2π  
                                     V s =   V a + e  3 V b +  e  3 V c ⋅ e − θ
                                                                j er
                                         3                                        (9.36)
                                         2     j 2π  − j 2 2π  
                                     I s =    I a + e  3  I b +  e  3  I c ⋅ e −  θ j er
                                                           
                                         3                
              Finally, the field circuit equations are

                                            dψ s
                                                                    s
                                 s
                                 iR F − V F = −  F  ;  ψ s F =  Li F + L dm( i d + )  (9.37)
                                                        s
                                        s
                                                        lF
                                 F
                                                                    i F
                                             dt
                s
             s
                      s
                   s
                         s
            V RL lF ,, ψ  are all reduced to the stator by a transformation (equivalent turns ratio) coefficient k .
             F ,
                F ,
                         F
                     i F
                                                                                          F
                                                                                       s
              Magnetic saturation may be modeled mainly by L  and L , which depend on i  = i  + i  and
                                                      dm
                                                             qm
                                                                               dm
                                                                                   d
                                                                                      F
            i  = i . The cross-coupling saturation has to be carefully considered for both steady-state and tran-
                 q
            qm
                                               a
            sient operation modes [4]. The active flux ψ  is [23]
                                               d
                                               a
                                                       q s
                                              ψ = ψ −  Li                             (9.38)
                                                    s
                                               d
              It turns to be the multiplier to of i  in the torque expression [23]
                                         q
                                        dm F −(
                                                                  a
                                   a
                                  ψ =  Li     d L − )  ;  e T =  3  p 1  ψ i q      (9.39)
                                                   q L
                                                      d i
                                   d                       2    d
              But this flux linkage is aligned along the d-axis of the rotor, and thus, its position is θ  and its
                                                                                    er
                     =  ˆ ω r  at all loads. Cross-coupling saturation introduces an error to θ , when estimated,
            speed  ˆ ω ψ d                                                  er
            which may be handled by adding a correction angle Δθ . For unity power factor, the steady-state
                                                         er
            equations and the vector diagram (Figure 9.32) are simplified to
   252   253   254   255   256   257   258   259   260   261   262