Page 147 - Shigley's Mechanical Engineering Design
P. 147

bud29281_ch03_071-146.qxd  11/24/09  3:02PM  Page 122 ntt 203:MHDQ196:bud29281:0073529281:bud29281_pagefiles:







                 122   Mechanical Engineering Design
                                                                                                            .
                                          This approximation is good for a large curvature where  e is small with  r n = r c .
                                          Substituting Eq. (3–66) into Eq. (3–64), with r n − y = r, gives

                                                                          . My r c
                                                                        σ =                                (3–67)
                                                                             I r
                                              .
                                          If r n = r c , which it should be to use Eq. (3–67), then it is only necessary to calculate r c ,
                                          and to measure y from this axis. Determining r c for a complex cross section can be done
                                          easily by most CAD programs or numerically as shown in the before-mentioned refer-
                                          ence. Observe that as the curvature increases, r → r c , and Eq. (3–67) becomes the
                                          straight-beam formulation, Eq. (3–24). Note that the negative sign is missing because y
                                          in Fig. 3–34 is vertically downward, opposite that for the straight-beam equation.



                       EXAMPLE 3–16       Consider the circular section in Table 3–4 with r c = 3 in and R = 1 in. Determine e by
                                          using the formula from the table and approximately by using Eq. (3–66). Compare the
                                          results of the two solutions.

                                Solution  Using the formula from Table 3–4 gives

                                                                R 2              1 2
                                                                                √        = 2.914 21 in
                                                     r n =        2   2   =        2
                                                         2 r c −  r − R    2 3 −  3 − 1
                                                                  c
                                          This gives an eccentricity of
                                Answer                      e = r c − r n = 3 − 2.914 21 = 0.085 79 in

                                              The approximate method, using Eq. (3–66), yields
                                                                      4
                                                          .  I     π R/4    R 2   1 2
                                Answer                  e =     =         =    =      = 0.083 33 in
                                                                       2
                                                            r c A  r c (π R )  4r c  4(3)
                                          This differs from the exact solution by −2.9 percent.



                                3–19      Contact Stresses

                                          When two bodies having curved surfaces are pressed together, point or line contact
                                          changes to area contact, and the stresses developed in the two bodies are three-
                                          dimensional. Contact-stress problems arise in the contact of a wheel and a rail, in auto-
                                          motive valve cams and tappets, in mating gear teeth, and in the action of rolling
                                          bearings. Typical failures are seen as cracks, pits, or flaking in the surface material.
                                              The most general case of contact stress occurs when each contacting body has a
                                          double radius of curvature; that is, when the radius in the plane of rolling is different
                                          from the radius in a perpendicular plane, both planes taken through the axis of the con-
                                          tacting force. Here we shall consider only the two special cases of contacting spheres
                                                              15
                                          and contacting cylinders. The results presented here are due to Hertz and so are fre-
                                          quently known as Hertzian stresses.


                                          15 A more comprehensive presentation of contact stresses may be found in Arthur P. Boresi and Richard
                                          J. Schmidt, Advanced Mechanics of Materials, 6th ed., Wiley, New York, 2003, pp. 589–623.
   142   143   144   145   146   147   148   149   150   151   152