Page 237 - Six Sigma Demystified
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Part 3  s i x   s i g m a  to o l s        217

                           Interpretation

                                                          2
                                                               2
                           We reject the null hypothesis if X   > X   for (r – 1)(c – 1) degrees of freedom,
                                                               α
                                                          0
                                   2
                           where X  is the chi-square value at the α level of significance.
                                   α
                             In the preceding example, the calculated p value from Excel and Minitab is
                           less than 0.05, so the null hypothesis is rejected, and we assert that there is a
                           difference between the male and female responses. Alternatively, the critical
                           value of the chi-square statistic at the 0.05 level of significance, with two
                           degrees of freedom, may be found from Appendix 3 as 5.991. Since the test
                           statistic exceeds the critical value, the null hypothesis is rejected.



                    Contour Plot


                           A contour plot is made up of curves, each having a constant value of a fitted
                           response. The curves have equally spaced values of the response. Additional
                           factors are set at selected values (usually their mean).

                           When to Use


                           Improve Stage

                             •	 Use in response surface analysis to determine where a maximum or min-
                                imum response is expected within or close to the data range

                           Methodology

                           For example, we can generate a contour plot for the model Y = 4.5 + 0.32x  –
                                                                                               1

                           0.63x . For any value of the response (Y), we can determine x  given x  or x
                                2
                                                                                                 2
                                                                                    1
                                                                                            2
                           given x .
                                 1
                             When y = 5, then 0.32x  – 0.63x  – 0.5 = 0. If x  = 0, then x  = – 0.5/0.63 =
                                                   1
                                                           2
                                                                        1
                                                                                   2
                           –0.794. If x  = 0, then x  = 0.5/0.32 = 1.56.
                                                1
                                     2
                             Thus the contour line for Y = 5 passes through the points (0, –0.79) and
                           (1.56, 0). We also can easily determine for Y = 5 the value of x  when x  = +1
                                                                                            1
                                                                                    2
                           and x  = –1 and the value of x  when x  = +1 and x  = –1. In this way, we then
                                                              2
                                1
                                                      1
                                                                         2
                           calculate other contour lines (for different y values).
                           Overlaid Contour Plots
                           Overlaid contour techniques provide a method for evaluating joint regions of
                           optimality for more than one response. In this technique, we lay one contour
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