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0593_C16_fm  Page 554  Tuesday, May 7, 2002  7:06 AM





                       554                                                 Dynamics of Mechanical Systems


                                                            
                                          δ x () = ( x 2  2) δ x () =  x 2  2  x >  0 ,  δ 0 () =  0  (16.10.6)
                                               D
                                                                               D
                                                       1
                                           3
                                                              0    x <  0  3
                                                            
                                          δ x () = ( x 3  6) δ x () =  x 3  6  x >  0 ,  δ 0 () =  0  (16.10.7)
                                               D
                                                                               D
                                                      1
                                           4
                                                              0   x <  0  4
                                                              n
                                        δ n+1  x () = ( x n) 1   xn!  x > 0 ,  δ n+1 () = 0  (16.10.8)
                                                                                D
                                              D
                                                      δ x () = 
                                                  n
                                                                              0
                                                     !
                                                              0    x < 0
                        Observe that the definitions:
                                               δ 0 () = δ 0 () =…=  δ 0 () = δ  0 () =  0     (16.10.9)
                                                2     3         n     n + 1
                       allow the functions to be continuous at x = 0.
                        Graphically, these functions may be represented as in Figure 16.10.1. Observe that except
                       for δ (x) all the functions are continuous at x = 0.
                           1
                        Observe further that just as δ n+1 (x) represents the integration (or antiderivative) of δ (x),
                                                                                                  n
                       it follows that δ (x) is the derivative of δ n+1 (x). This raises the question, however, as to the
                                    n
                       derivative of δ (x). From the definition of Eq. (16.10.1), we see that, if x ≠ 0, then dδ (x)/dx
                                                                                                1
                                   1
                       is zero. At x = 0, however, the derivative is undefined, representing an infinite change in
                       the function. Thus, we have:
                                                                  
                                                 dδ ()    D  δ  x () =  0  x ≠  0           (16.10.10)
                                                    x dx =
                                                             0
                                                   1
                                                                   ∞  x =  0
                        δ (x) is often referred to as  Dirac’s delta function  — analogous to Kronecker’s delta
                         0
                       function of Section 2.6. The analogy is seen through the “sifting” or “substitution” property
                       of the functions. Recall from Eq. (2.6.7) that we have:
                                                           δ v =  v                           (16.10.11)
                                                            ij j  i

                       Similarly, it is seen (see References 16.1 to 16.5) that:

                                                   b
                                                  ∫  fx () ()   f 0   b > ) 0                (16.10.12)
                                                          x dx = () (
                                                       δ
                                                         0
                                                  − b
                        or

                                                 b
                                                 ∫  fx () ( x a dx = () ( b >  a)            (16.10.13)
                                                          − )
                                                      δ
                                                                 f a
                                                       0
                                                 − b
                       Interpreting an integral as a sum, we see that Eqs. (16.10.11) and (16.10.11) are simply
                       discrete and continuous forms of the same procedure with analogous results.
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