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                                                       Rating of  the secondary distribution transformer = 30 MVA,
                                                       3310.4 kV,
                                                       zp = 10% (after applying the negative tolerance)
                                                       Load currents at different harmonics are recorded as follows:
                                    35.5
                33.4  kV        v~=-xxooov
                                    d3
                 I   60 kVA                            Harmonic order          Load current (A)
                                                       1 (fundamental)         400
                                                        3                        a
                                                        5                       50
                                                        7                       27.5
                                                        9                        a
              Figure 23.17  Phasor diagram for  Example 23.1   11               10
                                                       13                       5
                                                       aThe third harmonic was almost absent. hence It was not considered.
           :.  The rating of the capacitor banks should be chosen for   The  second  and  other  even  harmonics  were  also  insignificant.
                                                       Similarly,  higher  harmonics  (above the  thirteenth)  were  also
           = 3000 + 180                                insignificant. hence were not considered for ease of illustration
           = 31 80 kVAr.                                :.  Actual loading of  the system.
           For the  basic parameters of  the  reactor on a per phase   /h  = [400’  + 25 x 50‘  + 49 x 27.5’  + 121 x 1 o2 + 169 x 5’1”’
           basis
                                                                                              (23.2)
           I,=   ~   1000                                = 525.2, say, 525 A.
               35.5/&
             = 48.8 A                                  The ampere meters, however, indicated only 400 A. While it
                                                       appeared that the  line was  not fully  loaded, in fact,  it was
           and rating of  reactor, VI  . IC = 60 kVAr   loaded to its rated capacity of 525 A and was utilized by only
           .
           ..   vl =  60 x 1000 v                                         352  .
                                                                              1.e.
                     48.8                              400 x 0.88,  Le. 352 A or  - by 67%, considering the
                                                                          525
                 = 1229.5 V                            system p.f. at 0.88.
                                                        Let us assume the following line parameters:
                   1229.5
           and  X,= -                                   Phase displacement at fundamental frequency, Le. apparent
                    48.8                                p.f. as measured by a normal p.f. meter.
                 = 25.2 R
           If this is designed for, say, 200 Hz, then its inductance   cos $,  = 0.88 lagging (Figure 23.18(a))
                L=    25.2                              ...   $1  = 28.36”.
                   2 x  ZX 200
                 = 20 mH

         23.9.2  Studying and nullifying the effects of
               harmonics

         Example 23.2
         A distribution network 33 kV, three-phase 50 Hz feeding an
         industrial belt with a number of medium-sized factories some
         with non-linear loads and some with static drives and some
         with both. It was observed that while the lines were apparently
         running  reasonably loaded, the active  power supplied was
         much  below  the  capacity  of  the  network.  Accordingly,  a
         harmonic study  of  the  network was  conducted and  it was
         found that despite localized p.f. control by most factories, the   (2) Actual loading
         p.f. of the network itself was well below the optimum level and   (3)  Improved loading
         the voltage was also distorted by more than was permissible.   (4)  Extra loading capacity
         To  improve  this  network  to  an  acceptable  level,  we  have   generated by improving
         considered the following  load conditions, as were  revealed   the p.f.           the network
         through the analysis.                           (5)  Improved actual loading
         Rating  of  primary  distribution  transformer  =  30  MVA,
         132133 kV
         zp = 10% (after applying the negative tolerance)
                                                        Figure 23.18(a)  Enhanced capacity utilization of  the network
          I, = 525 A (Figure 23.18(a))                  with the improved p.f.
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